### A comment on ``${\mathfrak p}<{\mathfrak t}$''

by Shelah. [Sh:885]

Canadian Math Bulletin, 2009

Dealing with the cardinal invariants p and
t of the continuum we prove that m >= p = aleph_2 => t =
aleph_1 . In other words if MA_{aleph_1} (or a weak
version of this) then (of course aleph_2 <= p <= t and) p = aleph_2
=> p = t . This is based on
giving a consequence.

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